4[x-(4-x)]=7(x+1)

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Solution for 4[x-(4-x)]=7(x+1) equation:


Simplifying
4[x + -1(4 + -1x)] = 7(x + 1)
4[x + (4 * -1 + -1x * -1)] = 7(x + 1)
4[x + (-4 + 1x)] = 7(x + 1)

Reorder the terms:
4[-4 + x + 1x] = 7(x + 1)

Combine like terms: x + 1x = 2x
4[-4 + 2x] = 7(x + 1)
[-4 * 4 + 2x * 4] = 7(x + 1)
[-16 + 8x] = 7(x + 1)

Reorder the terms:
-16 + 8x = 7(1 + x)
-16 + 8x = (1 * 7 + x * 7)
-16 + 8x = (7 + 7x)

Solving
-16 + 8x = 7 + 7x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-7x' to each side of the equation.
-16 + 8x + -7x = 7 + 7x + -7x

Combine like terms: 8x + -7x = 1x
-16 + 1x = 7 + 7x + -7x

Combine like terms: 7x + -7x = 0
-16 + 1x = 7 + 0
-16 + 1x = 7

Add '16' to each side of the equation.
-16 + 16 + 1x = 7 + 16

Combine like terms: -16 + 16 = 0
0 + 1x = 7 + 16
1x = 7 + 16

Combine like terms: 7 + 16 = 23
1x = 23

Divide each side by '1'.
x = 23

Simplifying
x = 23

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